Somebody me with this geometry work

m∠EGF = 65°  and m∠CGF = 115°

Step-by-step explanation:

Given;

∠EFG = 50°

EF = FG

Solution,

In ΔEFG m∠EFG = 50° and EF = FG.

Since triangle is an isosceles triangle hence their base angles are always equal.

∴

Let the measure of ∠EGF  be x.

∴

Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."

m∠EFG + m∠FEG + ∠EGF = 180

Hence

m∠EGF = 65°  

Also 'The sum of angles that are formed on a straight line is equal to 180°."

m∠EGF + m∠CGF = 180°

65° + m∠CGF = 180°

m∠CGF = 180° - 65° = 115°

Hence m∠EGF = 65°  m∠CGF = 115°

l.jnl.j/n.m,lm,

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3