One zero of f(x)=x^3-2x^2-5x+6 is 1 what are other zeros of the function

The other zeros are -2 and 3.

Step-by-step explanation:

As 1 is a zero then (x - 1) is a factor so we divide:

x - 1 )x^3-2x^2-5x+6(x^2-x-6

        x^3-x^2

              -x^2-5x

              -x^2+x

                      -6x+6    

                      -6x+6

x^2 - x - 6 = 0

(x - 3)(x + 2)

x = -2, 3.

-2 and 3

Step-by-step explanation:

Given one zero of f(x)=x^3-2x^2-5x+6 to be 1 this means that x-1 is a factor of the polynomial x³-2x²-5x+6

Before we can get the other two factors. We need to divide the polynomial function by x-1 and factorize the resulting quotient as shown in the attachment.

Quotient Q(x) = x²-x-6

Factorizing this function

x²-3x+2x-6 = 0

x(x-3)+2(x-3) = 0

(x+2)(x-3) = 0

x+2 = 0 and x-3 = 0

x = -2 and x= 3

Therefore the other zeros of the function are -2 and 3

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step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c