In δabc shown below, line segment ab is congruent to line segment bc: triangle abc, where sides ab and cb are congruent given: line segment ab≅line segment bc prove: the base angles of an isosceles triangle are congruent. the two-column proof with missing statement proves the base angles of an isosceles triangle are congruent: statement reason 1. segment bd is an angle bisector of ∠abc. 1. by construction 2. ∠abd ≅ ∠cbd 2. definition of an angle bisector 3. segment bd ≅ segment bd 3. reflexive property 4. 4. side-angle-side (sas) postulate 5. ∠bac ≅ ∠bca 5. cpctc which statement can be used to fill in the numbered blank space?

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

2 pecks

step-by-step explanation:

divide the numbers

step-by-step explanation:

well in order to answer the question, you have to give us the dimensions of the prism first.