Xpress the integral f(x, y, z) dv e as an iterated integral in six different ways, where e is the solid bounded by the given surfaces. y = x2, z = 0, y + 3z = 9 −3 x2 f(x, y, z) dz dy dx 0 0 − y f(x, y, z) dz dx dy 0 0 0 f(x, y, z) dx dz dy − y 0 0 f(x, y, z) dx dy dz − y −3 0 f(x, y, z) dy dz dx x2 0 − 9−3z f(x, y, z) dy dx dz x2

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

∞ this is your sign

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches

the answer to your question is minor arc.