Assume you are working with a standard deck of 52 cards. there are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace) in each of four suits (clubs, diamonds, hearts, and spades). what is p(ace ∪ heart) if you draw one card?

answer:

1) 60% have a valid license, so 40% do not have a valid license

of the 60% with a valid license, 70% had no violations (100%-30%=70%)

70%*60%=0.7*0.6=0.42=42% had   no violations

of the 40% that had no valid license, 80% had no violations (100%-20%=80%)

80%*40%=0.8*0.4=0.32=32% had no violations

42%+32%=74% with no violations

2)what is the probability of drawing an ace or a heart

there are 4 aces and 13 hearts but one heart is an ace so you can't use the ace of hearts twice

p=(4+12)/52=16/52=4/13 or

p=(3+13)/52=16/52=4/13, or

p=(4/52)+(13//52)=(4+13-1)/52=16/52=4/13

step-by-step explanation:

b

step-by-step explanation:

if a was wrong then it has to be b it cant be c either because not all the y intercepts are the same!

ok now , i would like brainlest plz

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.