The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days.

a) find the probability of a pregnancy lasting 308 days or longer.
b) if the length of pregnancy is in the lowest 22? %, then the baby is premature.

find the length that separates premature babies from those who are not premature.

a) the probability that a pregnancy will last 308 days or longer is?
b) babies who are born on or before days are considered premature

a) P(X>308) = 0.00383

b) 256.42 days

Step-by-step explanation:

Population mean (μ) = 268 days

Standard deviation (σ) = 15 days

a) P(X>308)?

The z-score for any length of pregnancy 'X' is given by:

The z-score for X=308 is:

A z-score of 2.6667 is equivalent to the 99.617-th percentile of a normal distribution. Thus, the probability of a pregnancy lasting 208 days or longer is:

b) X at which P(X) < 0.22?

At the 22-nd percentile, a normal distribution has an equivalent z-score of -0.772. Therefore, the length of pregnancy, X, that separates premature babies from those who are not premature is:

(2,6)

step-by-step explanation:

cause i just did this and got the answer

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