Use technology to find the p-value for the hypothesis test described below.
the claim is that for a smartphone carrier's data speeds at airports, the mean is μ=18.00 mbps.
the sample size is n=17 and the test statistic is t=−1.421.

what is the p-value?
(round to three decimal places as needed.)

The p-value is 0.175

Step-by-step explanation:

We have the null hypothesis and the alternative hypothesis (two-tailed alternative). Because the sample size is n = 17 and the test statistic is t=-1.421, we know that this last value comes from a t distribution with n-1=17-1=16 degrees of freedom. Therefore, the p-value is given by 2P(T < -1.421) because the p-value is the probability of getting a value as extreme as the observed value and because of the simmetry of the t distribution. Here, T has a t distribution with 16 df and we are using the t distribution because the sample size is small. So, 2P(T < -1.421) = 0.1745

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

$5.41

step-by-step explanation:

$20 - $14.51 = $5.49.