Mathematics, 03.12.2019 18:31, maleja2038
The volume v, in liters, of air in the lungs during a five-second respiratory cycle is approximated by the model v + 0.1729t + 0.1522t² - 0.0374t³, where t is the time in seconds. approximate the average volume of air in the lungs during one cycle.
Answers: 1
, where t is the time in seconds. 
![V_a=\frac{1}{5}[\frac{0.1729t^2}{2}+\frac{0.1522t^3}{3}- \frac{0.0374t^4}{4}}]^5_0](/tpl/images/0401/2921/29fdd.png)
![V_a=\frac{1}{5}[0.08645t^2+0.05073t^3- 0.00935t^4]^5_0](/tpl/images/0401/2921/778db.png)
![V_a=\frac{1}{5}[0.08645(5)^2+0.05073(5)^3- 0.00935(5)^4-0.08645(0)^2+0.05073(0)^3- 0.00935(0)^4]](/tpl/images/0401/2921/1418a.png)
![V_a=\frac{1}{5}[2.1613+6.3413-5.8438]](/tpl/images/0401/2921/c7b18.png)
![V_a=\frac{1}{5}[2.6588]](/tpl/images/0401/2921/ae09b.png)
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The volume v, in liters, of air in the lungs during a five-second respiratory cycle is approximated...
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