Mathematics

Mathematics, 03.12.2019 08:31, tfracciscoramon

15.
i know that the top one is incorrect but i don’t understand why or how to the correct answer.

15. i know that the top one is incorrect but i don’t understand why or how to the correct answ

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Chemistry, 23.09.2019 05:30, desi9750

Can someone tell my why my answer is incorrect and what the correct answer is? i don’t understand how this is wrong

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Mathematics, 19.11.2019 02:31, annabelle2516

Example 5 suppose that f(0) = −7 and f '(x) ≤ 8 for all values of x. how large can f(3) possibly be? solution we are given that f is differentiable (and therefore continuous) everywhere. in particular, we can apply the mean value theorem on the interval [0, 3] . there exists a number c such that f(3) − f(0) = f '(c) 3 correct: your answer is correct. − 0 so f(3) = f(0) + 3 correct: your answer is correct. f '(c) = −7 + 3 correct: your answer is correct. f '(c). we are given that f '(x) ≤ 8 for all x, so in particular we know that f '(c) ≤ 8 correct: your answer is correct. multiplying both sides of this inequality by 3, we have 3f '(c) ≤ 24 correct: your answer is correct. , so f(3) = −7 + incorrect: your answer is incorrect. f '(c) ≤ −7 + incorrect: your answer is incorrect. = incorrect: your answer is incorrect. the largest possible value for f(3) is .

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Mathematics, 20.11.2019 17:31, marleas

Let z denote a variable that has a standard normal distribution. determine the value z* to satisfy the conditions below. (round all answers to two decimal places.) (a) p(z < z*) = 0.0244 z* = -1.97 correct: your answer is correct. (b) p(z < z*) = 0.0101 z* = -2.32 correct: your answer is correct. (c) p(z < z*) = 0.0502 z* = -1.64 correct: your answer is correct. (d) p(z > z*) = 0.0199 z* = 2.06 correct: your answer is correct. (e) p(z > z*) = 0.0101 z* = 2.33 incorrect: your answer is incorrect. (f) p(z > z* or z < -z*) = 0.1974 z* = .86 incorrect: your answer is incorrect.

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Mathematics, 12.12.2019 23:31, bree9362

Example 5 suppose that f(0) = −7 and f '(x) ≤ 8 for all values of x. how large can f(3) possibly be? solution we are given that f is differentiable (and therefore continuous) everywhere. in particular, we can apply the mean value theorem on the interval [0, 3] . there exists a number c such that f(3) − f(0) = f '(c) 3 correct: your answer is correct. − 0 so f(3) = f(0) + 3 correct: your answer is correct. f '(c) = −7 + 3 correct: your answer is correct. f '(c). we are given that f '(x) ≤ 8 for all x, so in particular we know that f '(c) ≤ 8 correct: your answer is correct. multiplying both sides of this inequality by 3, we have 3f '(c) ≤ 24 correct: your answer is correct. , so f(3) = −7 + incorrect: your answer is incorrect. f '(c) ≤ −7 + incorrect: your answer is incorrect. = incorrect: your answer is incorrect. the largest possible value for f(3) is .

Answers: 2

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