Triangle xyz is translated 4 units up and 3 units left to yield triangle x'y'z'. what is the distance between any two corresponding points on triangle xyz and triangle x'y'z'?

Answer

5 units

Explanation

The translation of the points X<Y and Z makes a right triangle with legs 3 units and 4 units.

The distance between the correspong is the hypotenuse of the triangle.

Using the Pythagoras theorem;

c² = a² + b²

Where a and b are the legs and c is the hypotenuse.

c²   = 3² + 4²

      = 9 + 16

       = 25

c    = √25

      = 5 units

2 5/8 is the final answer! : )