Aprob 140 student comes to lecture at a time that is uniformly distributed between 5: 09 and 5: 14. independently of the student, the professor begins the lecture at a time that is uniformly distributed between 5: 10 and 5: 12. what is the chance that the lecture has already begun when the student arrives?

it's 100

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

  n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the  14th  row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

read more on -

your answer is false.

replace the variable (x) with -3. insert it using parenthesis like this:

-35(-3) = -105

this statement is false because -35 multiplied by -3 is 105, not -105.