Tory and quentin are the same age. tory’s younger sister is the same age as quentin’s younger brother. tory is 3 years older than her sister. quentin’s age is 8 years less than twine his brother’s age. write and solve an equation to determine tory’s and quentin’s ages.

Let Tory’s sister age = x

Since Tory is 3 years older than her sister ,

Tory = (x + 3)

let Quentin’s brother age = x

( because quentin’s brother & tory’s sister are the same age , we can let both their ages be x )

Since Quentin is 8 years less than twice his brother’s age ,

Quentin = (2x -8)

Since Quentin and Tory are the same age ,

x + 3 = 2x - 8

-x = -8-3
x = 11

Ans : 11 years old :)

I’m so sorry if this is incorrect

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.