One number is 5 more than twice the other number. if the sum of the two numbers is 32 find the two numbers

  9 and 23

Step-by-step explanation:

You can adjust the problem a little bit and make it easier to solve.

Subtracting 5 from the larger number makes it twice the smaller, and their sum be 32-5 = 27. So 27 is 3 times the smaller number, 9, and the larger is 32-9 = 23, which is 5 more than two times 9.

The two numbers are 9 and 23.

You can let x represent "the other number". Then "one number" is 2x+5, and their sum is ...

  (x) +(2x+5) = 32

  3x +5 = 32

  3x = 27 . . . . . subtract 5

  x = 9 . . . . . . . divide by 3

(This working out should look familiar if you followed the above verbal solution.)

"One number" is 27 and "the other number" is 9.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: