(d) suppose that johanna's acceleration is positive for the interval 12 < t < 20 seconds. given that johanna's position at t=12 is 150 meters, explain why the position of the particle at t=20 must be greater
than 1700 meters.

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c

answer is c

step-by-step explanation:

81/12=324/x

x=48