Arectangular yard measuring 26 ft by 36 ft is bordered (and surrounded) by a fence. inside, a walk that is 2 ft wide goes all the way along the fence. find the
area of this walk. be sure to include the correct unit in your answer.

e
swww
de des
bow />n

ssbbw

=
x
te
5
?
deel
- baba
berbeda
s
suffe
dete
ed
peelgoed
sede ele
gb
fe
low
teateelse
el

t

em
w
arty
model />eten />
be
te
/>
ele
p
/>la

  232 square feet

Step-by-step explanation:

The outside dimensions of the yard are 26 ft by 36 ft, so its total area is ...

  yard including walk = (26 ft)(36 ft) = 936 ft²

The dimensions of the yard inside the walkway are 22 ft by 32 ft, so that area is ...

  yard not including walk = (22 ft)(32 ft) = 704 ft²

The difference in these areas is the area of the walkway:

  walkway area = (yard including walk) - (yard not including walk)

  = (936 -704) ft² = 232 ft² . . . . area of the walk

Another way to figure this is to consider the length of the centerline of the walkway. That is the perimeter of a rectangle that is 24 ft by 34 ft. The perimeter (centerline length) is 116 ft, and the width of the walk is 2 ft, so its area is ...

  (116 ft)(2 ft) = 232 ft²

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

idk

step-by-step explanation: