how many x-intercepts appear on the graph of this polynomial function?
1 rx)= x -x + x²-x
1 x-intercept
2 x-intercepts
3 x-intercepts
4 x-intercepts

The given function has 2 x -intercepts.

Step-by-step explanation:

Here, the given polynomial function is :

or,   ............  (1)

X- intercept is the point in the graph of R(x), where the coordinate y = 0.

Now, substituting the value of y  =  0 in (1) find all x - intercepts:

⇒ Either x = 0 ,         or x - 1 = 0 ⇒  x = 1

⇒The given function has two x intercepts at x  = 0 and x = +1

Hence, the given function has 2 x -intercepts.

ok

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)