Factor the polynomial x^4-16. how many real zeros does the function g(x)=x^4-16 have?

(x-2)(x+2)(x^2 + 4)

Step-by-step explanation:

This can be done by difference of squares:

(x^2 - 4) (x^2 + 4)

And now (x^2 - 4) can be further factored:

(x-2)(x+2)(x^2 + 4) is your answer

Clearly, There are only 2 zeroes that we can get from this, 2 and -2

Hope this helps!

If you think I helped please mark brainliest! Would really appreciate!

Step-by-step explanation:

The zeros of g(x):