There are three consecutive integers. the sum of the first two is 35 more than the third. find the integers.
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Let the three numbers be a-1,a and a+1 (since they are consecutive).
According to question
(a-1) + (a) = 35 + (a+1)
Solving this equation, we get
a=37
Therefore the three numbers are (37-1),37,(37+1) i.e 36,37,38.