The annual interest on an $20,000 investment exceeds the interest earned on a $4000 investment by $1320. the $20,000 is invested at a 0.6% higher rate of interest than the $4000. what is the interest rate of each investment? $20,000 is invested at what %$4,000 is invested at what %

"8.8%"

Step-by-step explanation:

Let x be the interest rate for the 20,000 and y for the 4,000

The problem says:

x20,000 = y4,000+1320 (1)

and

x = y+0.006 Substitute this value for x on equation (1)

(y+0.006)20,000 = y4,000+1320

20,000y+120 = y4,000+1320

16,000y = 1320

y = 0.0825 So the 4,000 are invested at 8.25%

And since x = y+0.006:

x = .0825+0.006 = 0.0885 or 8.8%. The 20,000 are invested at 8.8%

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,

95.03 is the answer. hope this !