You select a family with three children. if m represents a male child, and f represents a female child, the set of equally likely outcomes for the children's genders is { mmm, mmf, ffm, mff, ffm, fmf, ffm, fff }. find the probability of selecting a family with nothing 6 male children.

1/8

Step-by-step explanation:

This is actually pretty easy.

First, you have the sample of the children.

You know that the family with 3 children, can only have the following children:

MMM: all males

MMF: 2 males, 1 female

MFF: 1 male, 2 females

MFM: 2 males, 1 female (different order)

FMM: 1 female, 2 males

FFM: 2 females, 1 male

FMF: 2 females, 1 male

FFF: 3 females

If you count all of these possibilities, we have 8 possible cases of family with the childrens.

In only one of them, we have only females and no males, which is the last one, all 3 females.

Therefore, the probability to select a family with no male, is only 1/8.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen