An engineer wishes to determine the width of a particular electronic component. if she knows that the standard deviation is 1.6 mm, how many of these components should she consider to be 99% sure of knowing the mean will be within ±0.1±0.1 mm? a. 16 b. 4349 c. 1386 d. 42 e. 1699

n=1705

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Assuming the X follows a normal distribution  

And the distribution for is:

We know that the margin of error for a confidence interval is given by:  

  (1)  

The next step would be find the value of , and  

Using the normal standard table, excel or a calculator we see that:  

If we solve for n from formula (1) we got:  

And we have everything to replace into the formula:  

And if we round up the answer we see that the value of n to ensure the margin of error required mm is n=1705.  

this doesn't make sense lol

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all