Seed mixture x is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture y is 25 percent ryegrass and 75 percent fescue. if a mixture of x and y contains 30 percent ryegrass, what percent of the weight of the mixture is x ?

The weight of X is of weight of mixture.

Step-by-step explanation:

Since we have given that

Percentage of seed mixture X for ryegrass = 40%

Percentage of seed mixture Y for ryegrass = 25%

If a mixture of X and Y contains 30 percent ryegrass,

Let total seed mixture be 100

So, for seed X = x

For seed Y = 100-x

So, According to question,

So, weight of mixture X is given by

Hence, the weight of X is of weight of mixture.

step-by-step explanation: