Atelevision news program conducts a call in poll about a proposed city ban on handgun ownership. of the 2372 calls,1921 oppose the ban. the station, following recommended practice, makes a confidence statement: "81% of the channel 13 pulse poll sample opposed the ban. we can be 95% confident that the true proportion of citizens opposing a handgun ban is within 1.6% of the sample result." is this conclusion justified?

We can be 95% confident that the true proportion of citizens opposing a handgun ban is within 1.6% of the sample result.

is true.

Step-by-step explanation:

Given that a television news program conducts a call in poll about a proposed city ban on handgun ownership. Of the 2372 calls,1921 oppose the ban. The station, following recommended practice, makes a confidence statement:

Sample proportion p =

q=1-p =

Std error of p =

Margin of error for 95%=1.96*std error = 0.0158

Since margin of error is 0.0158 i.e. nearly 15.8% and proportion is 0.8099 = 81%

the statement is correct.

We can be 95% confident that the true proportion of citizens opposing a handgun ban is within 1.6% of the sample result.

is true.

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.