Cloud seeding has been studied for many decades as a weather modification procedure (for an interesting study of this subject, see the article in technometrics, "a bayesian analysis of a multiplicative treatment effect in weather modification," 1975, vol. 17, pp. 161–166). the rainfall in acre-feet from 20 clouds that were selected at random and seeded with silver nitrate follows: 18.0, 30.7, 19.8, 27.1, 22.3, 18.8, 31.8, 23.4, 21.2, 27.9, 31.9, 27.1, 25.0, 24.7, 26.9, 21.8, 29.2, 34.8, 26.7, and 31.6. a) can you support a claim that mean rainfall from seeded clouds exceeds 25 acre-feet? use α =

One positive number is 9 more than twice another. if their product is 95, find the numbers

Write 5(6x+4)-2(5x-2) in the form a(bx+c) where a, b and c integers and a> 1

On a certain portion of an experiment, a statistical test result yielded a p-value of 0.21. what can you conclude? 2(0.21) = 0.42 < 0.5; the test is not statistically significant. if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time, so the test is not statistically significant. 0.21 > 0.05; the test is statistically significant. if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 79% of the time, so the test is not statistically significant. p = 1 - 0.21 = 0.79 > 0.05; the test is statistically significant.