How would you describe the relationship between the real zeros and x-intercepts of the function y=log4(x-2)

Step-by-step explanation:

First, look at y = log x.  The domain is (0, infinity).  The graph never touches the vertical axis, but is always to the right of it.  A real zero occurs at x = 1, as log 1 = 0 => (1, 0).  This point is also the x-intercept of y = log x.

Then look at y = log to the base 4 of x.  The domain is (0, infinity).  The graph never touches the vertical axis, but is always to the right of it.  Again, a real zero occurs at x = 1, as log to the base 4 of 1 = 0 => (1, 0).

Finally, look at y=log to the base 4 of (x-2).  The graph is the same as that of y = log to the base 4 of x, EXCEPT that the whole graph is translated 2 units to the right.  Thus, the graph crosses the x-axis at (3, 0), which is also the x-intercept.

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

answer: options

step-by-step explanation: