Me pl

seth is using the figure shown below to prove the pythagorean theorem using triangle similarity:

in the given triangle def, angle d is 90° and segment dg is perpendicular to segment ef.

the figure shows triangle def with right angle at d and segment dg. point g is on side ef.

part a: identify a pair of similar triangles. (2 points)

part b: explain how you know the triangles from part a are similar. (4 points)

part c: if eg = 2 and ef = 8, find the length of segment ed. show your work. (4 points)

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

answer: 100

step-by-step explanation:

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )

its   c, f, a

step-by-step explanation: