Aregular type of laminate is currently being used by a manufacturer of circuit boards. a special laminate has been developed to reduce warpage. the regular laminate will be used on one sample of specimens and the special laminate on another sample, and the amount of warpage will then be determined for each specimen. the manufacturer will then switch to the special laminate only if it can be demonstrated that the true average amount of warpage for that laminate is less than for the regular laminate. state the relevant hypotheses. h0: μregular = μspecial ha: μregular < μspecial h0: μregular = μspecial ha: μregular > μspecial h0: μregular > μspecial ha: μregular = μspecial h0: μregular < μspecial ha: μregular = μspecial h0: μregular = μspecial ha: μregular ≠ μspecial describe the type i error in the context of this situation.

the answer is c. 23/3

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).

the answer is a.

135 and 80

step-by-step explanation: