An inspection procedure at a manufacturing plant involves picking three items at random and then accepting the whole lot if at least 2 of the three items are in perfect condition. if in reality 84% of the whole lot are perfect, what is the probability that the lot will be accepted?

We use the Binomial Distribution   where p =.84 then probability will be 0.931.

Step-by-step explanation:

P(X≥ 2) = P(X=2) + P (X=3)

           = (³₂)(.84)^2(.16) +  (³3)(.84)^3(.16)⁰

           ≅ 0.931

Hence 0.931 is the answer.

493 would be the correct answer

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