Achemist needs 70 milliliter of 29% solution but has only 19% and 33% solutions available. find how many milliliter of each that should be mixed to get the desired solution

Step-by-step explanation:

Let x represent the volume in mL of 33% solution needed. Then 70-x is the volume of 19% solution required. The total amount of solute is ...

  0.33x + 0.19(70 -x) = 0.29(70)

  0.14x = 70(0.29 -0.19)

  x = 70(0.10/0.14) = 50

50 mL of 33% solution should be mixed with 20 mL of 19% solution to get the desired mix.

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)