How to prove that the square root of 3 and 5 is irrational?

Step-by-step explanation:

Let us assume, the contrary √3 is a rational no.√3 = p/q ,where p and q are co-prime p = √3qsquaring on both sides/3 =.............................(1)3 is a factor of pp = 3c , where c is some constantsubstituting p = 3c in equation (1)9 = 3/3 =

       ∴ 3 is also a factor of q

But , this is a contradiction.we have assume p and q are co prime

       ∴ √3 is an irrational no.

Similarly, for √5