Mathematics, 27.11.2019 22:31, notmclovinyou

What is the equation of the line that passes through the point (5,4) and is perpendicular to the line whose equation is 2x + y = 3in standard form?
2x+y=3y=-2x+3
m=-2m=1/2
y-4=1/2(x-5)

Answers: 2

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Answers

The equation of the line that passes through the point (5,4) and is perpendicular to the line whose equation is 2x + y = 3 in standard form is x - 2y = - 3

Solution:

Given, line equation is 2x + y = 3

2x + y – 3 = 0 ----- eqn (1)

We have to find a line that is perpendicular to 2x + y – 3 = 0 and passing through (5, 4).

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{1}=-2$

$\text { Slope of a line } \times \text { slope of perpendicular line }=-1$

$\begin{array}{l}{-2 \times \text { slope of perpendicular line }=-1} \\\\ {\text { Slope of perpendicular line }=-1 \times \frac{1}{-2}=\frac{1}{2}}\end{array}$

Now, slope of our required line = 1/2 and it passes through (5, 4)

The point slope form is given as:

$y-y_{1}=m\left(x-x_{1}\right)$

$\text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }$

$\text { Here in our problem, } \mathrm{m}=\frac{1}{2}, \text { and }\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)=(5,4)$

$y-4=\frac{1}{2}(x-5)$

Now let us convert to standard form:

The standard form of a line is just another way of writing the equation of a line.

The standard form of an equation is Ax + By = C. In this kind of equation, x and y are variables and A, B, and C are integers.

2(y – 4) = 1(x - 5)

2y – 8 = x – 5

x – 2y - 5 + 8 = 0

x - 2y + 3 = 0

x - 2y = - 3

Hence, the line equation in standard form is x - 2y = - 3

answered: Guest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is