Two urns each contain green balls and blue balls. urn i contains 4 green balls and 6 blue balls, and urn ii contains 6 green balls and 2 blue balls. a ball is drawn at random from each urn. what is the probability that both balls are blue?

a. 2/51

b. 3/20

c. 1/10

d.4/153

B.

Step-by-step explanation:

Let A be the event that a blue ball is drawn from urn l and let B be the event that a blue ball is drawn from urn ll.

Then P(A)=

and P(B)=

As both the events are independent, thus the probability that both balls are blue =

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

the correct answer is a) "catholic church".

the proposals that liberals in mexico made during 1855 were particularly focused on a person's individual rights, such as the freedom of speech, the freedom of conscience, freedom of assembly, and the right to possess weapons.

when the constitution was formally published 2 years later (1857). it also contained an article which permitted education free from any religious influence, the removal of the catholic church institutional privileges, and the sale of property belonging to the church. all of these provisions were clearly against the catholic church interests.