In a recent poll of 1200 randomly selected adult office workers, 32% said they had worn a halloween costume to the office at least once. report the 95% confidence interval for the proportion of all adult office workers who have worn a halloween costume to the office at least once. (round final calculations to the nearest tenth of a percent)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

, where = sample proportion.

z* = critical value (Two-tailed)

n= Sample size ;

In the given problem , we are given

n= 1200

Also, we know that the critical value for 95 %confidence interval : z*= 1.96

Now, the 95% confidence interval for the proportion of all adult office workers who have worn a Halloween costume to the office at least once will be :-

Hence, the required confidence interval =

a. (14,375+570)(5.3) b. 158,417$

step-by-step explanation:

a. you are basically just setting up the equation. f= amount of debt hence 14,375. g= how much she is borrowing from her parents weekly hence 570 and t= the interest on her debt. creating the equation.

b.   14,375+570= 14,945

      14,945 x 5.3 = 79,208.5

      79,208.5 x 2(years) = 158,417(answer)

2

step-by-step explanation: