If a fair coin is flipped 15 times, what is the probability that there are more heads than tails?

The probability that there are more heads than tails is equal to .

Step-by-step explanation:

Since the number of flips is an odd number, there can't be an equal number of heads and tails. In other words, there are either

Let the event that there are more heads than tails be . (i.e., not A) denotes that there are more tails than heads. Either one of these two cases must happen. As a result, .

Additionally, since this coin is fair, the probability of getting a head is equal to the probability of getting a tail on each toss. That implies that (for example)

Due to this symmetry,

In other words .

Combining the two equations:

,

.

In other words, the probability that there are more heads than tails is equal to .

This conclusion can be verified using the cumulative probability function for binomial distributions with as the probability of success.

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what? ?

what type of question is thiss

step-by-step explanation:

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get