The asq (american society for quality) regularly conducts a salary survey of its membership, primarily quality management professionals. based on the most recently published mean and standard deviation, a quality control specialist calculated thez-score associated with his own salary and found it was minus2.50. what is his salary? a. 2.5 standard deviations below the average salary. b. 2 and a half times less than the average salary. c. 2.5 standard deviations above the average salary. d. 2 and a half times more than the average salary.

A. 2.5 standard deviations below the average salary.

Step-by-step explanation:

Hello!

Usually, when you calculate a probability of an X₀ value from a normally distributed variable you need to standardize it to reach the proper value. In this case, you already have the Z-value and need to reverse the standardization to obtain the X₀ value.

Z= X₀ - μ

δ

δ*Z = X₀ - μ

X₀= (δ*Z) + μ

replace Z= -2.50

X₀= (δ*-2.50) + μ

X₀= μ - (δ*2.50)

You can replace the Z value any time. I've just choose to do it at the end because it's more confortable for me.

I hope it helps!

answer:  

123455421

step-by-step explanation: easy

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.