Erse trigonometric functions to solve the following equations. if there is more than one solution, enter all solutions as a comma-separated list (like "1, 3) if an equation has no solutions, enter a solve 5 sin(θ)-1 for θ (where 0 θ < 27 preview b. solve 11 sin(θ)-11 for θ (where 0 < θ < 2π). preview θ preview c solve 5 sin(θ)-: 14 for θ (where 0 2π). submit licesse question 9. points possible: 3 unlimited attempts message instructor about this question post this question to forum use inverse trigonometric functions to solve the following equations. if there is more than one solution, enter all solutions as a comma-separated list (like "1, 3") if an equation has no solutions, enter "dne" a. solve for e (where 0 s θ < 2π). preview b, solve 7 tan(θ) = -16 for θ (where () "c 2n) preview submit question 10. points possible: 2 unlimited attempts

the answer for your question is

step-by-step explanation:

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: