Asurvey was conducted that asked 1003 people how many books they had read in the past year. results indicated that x overbar equals 12.8 books and sequels 16.6 books. construct a 99% confidence interval for the mean number of books people read. interpret the interval.

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

represent the sample deviation

represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of and , with that value we can find the quantile required for the interval in the normal standard distribution.

And replacing into the confidence interval formula we got:

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

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step-by-step explanation:

just for that im not answering

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation