Acompany makes auto batteries. they claim that 86% of their ll70 batteries are good for 70 months or longer. assume that this claim is true. let p be the proportion in a random sample of 80 such batteries for a populations that are good for 70 months or more.
what is the probability that this sample proportion is within 0.03 of the population proportion?

The probability that the sample proportion of 80 LL70 batteries is within 0.03 of the population proportion is 0.44

Step-by-step explanation:

Sample proportion being within margin, or margin of error (ME) around the mean can be found using the formula

ME= where

z is the corresponding statistic of the probability that the sample proportion is within the 0.03 of the population proportionp is the claimed proportion (86% or 0.86) N is the sample size (80)

Then 0.03= from this we get:

z≈0.773 and the p(z)≈0.439

Therefore, the probability that the sample proportion is within 0.03 of the population proportion is 0.44

B) greg: 30 points , tremaine 38 points

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote