The perimeter of a rectangle field is 118m. if the length of the rectangle is 7m less than twice the width what is the length

Let:

P - perimeter

l - length

w - width

We know:

P = 118 m

l = 2w - 7

We replace the length with 2w - 7.

P = 2×(2w - 7) + 2w

118 = 4w - 14 + 2w

118 = 6w - 14

6w = 118 + 14

6w = 132

w = 22 meters

w = 22 l = 37

Explanation:

Perimeter = P

Length = l

Width = w

Formula: P = 2 ( w + l ) + 2w

We know

P = 118

l = 2w - 7

Solve

P = 2 (2w - 7) + 2w

118 = 4w - 14 + 2w

118 = 6w - 14

+14          +14

132 = 6w

 6       6

w = 22

2(22) - 7

44 - 7 = 37

l = 37

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get