Apoll found that 64% of a random sample of 1076 adults said they believe in ghosts.

question 1. find the margin of error -/n), abbreviated me, for this poll if we want 90% confidence in our estimate of the proportion of adults who believe in ghosts.
me=

(round to 3 decimal places.)

question 2. find the margin of error needed to be 99% confident.
me= (round to 3 decimal places.)

Margin of error at 90% is 0.024

Margin of error at 99% is 0.037

Step-by-step explanation:

Sample size = 1076

A poll found that 64% of a random sample of 1076 adults said they believe in ghosts.

So, No. of adults said they believe ghosts =

So, x = 688

n = 1076

z at 90% confidence is 1.64

So, margin of error at 90% is 0.024

Find the margin of error needed to be 99% confident.

z at 99% confidence is 2.58

So, margin of error at 99% is 0.037

step-by-step explanation:

their are no angles. sorry cant .

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt