The path of a soccer ball after it is
kicked from a height of 0.5 m above
the ground is given by the equation
h = -0.1d^2+ d + 0.5, where h is the
height, in wetres, above the ground and
d is the horizontal distance, in metres.
a) how far has the soccer ball travelled
horizontally, to the nearest tenth of a
metre, when it lands on the ground?

Distance=slopeslope is -2/4which equals-1/2the distance between these two points is -1/2

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Look, when you want to do something like put it like x^2. x2 could mean x² or x₂. so to clear confusion, know the notation. to find the product multiply the x's and you get -8x and the y's and you get 6y. since it's all being multiplied it is just -8x6y, or answer a. although the better answer is -48xy(combining -8 and 6) because you should multiply constants whenever you can.