)find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s. p1: 1 ch08-7t rosen-2311t mhia017-rosen-v5.cls may 13, 2011 16: 25 8.1 applications of recurrence relations 511 b) what are the initial conditions? c) how many bit strings of length seven contain two consecutive 0s?

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

step-by-step explanation:

left be aligning the decimal points is required to not required see the number of digits to the right

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.