Arectangles length x is 2 meters greater than it’s width if the perimeter of the rectangle is greater than 112 meters what is the rectangles possible length x in meters

The length must be greater than 29 m

Step-by-step explanation:

Length of the rectangle: x. It must be 2 meters greater than its width w, so

x = w + 2

Perimeter of a rectangle = sum of its sides = 2*x+2*w

P = 2(w+2)+2w = 4+4w

The perimeter must be greater than 112 m, so

4+4w > 112

4w > 108

w > 27, or

x - 2 > 27

x > 29

The length must be greater than 29 m

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)