The perpendicular bisector of side ab of triangle abc intersects the extension of side ac at d. find the measure of angle abc if measurement of angle cbd=16 degrees and measurement of angle acb=118 degrees

  23°

Step-by-step explanation:

Let the interior angles of ΔABC be referenced by A, B, and C. The definition of point D means that ΔDAB is an isosceles triangle, so we have the relations ...

  A + B + 118 = 180 . . . . interior angles of ΔABC

  A = B +16 . . . . . . . . . . base angles of ΔDAB

Using the expression for A in the second equation to substitute into the first equation, we get ...

  (B+16) +B +118 = 180

  2B + 134 = 180 . . . . . collect terms

  2B = 46 . . . . . . . . . . . subtract 134

  B = 23 . . . . . . . . . . . . divide by 2

m∠ABC = 23°

the answers c

529 and 531

step-by-step explanation: