Awoman has money in two accounts. one account pays 5% annual interest, whereas the other pays 10% annual interest. if she has $800 more invested in 10% than she does at 5% and her total interest for a year is $250, how much does she have in each account?

She have $1133.33 in account which pays  5% annual interest and he have $1933.33 in account which pays 10% annual interest

Step-by-step explanation:

Let x be the amount she invested at 5% annual interest

She invested $800 more in 10%

So, she invested x+800 at 10% annual interest

Case 1:

Principal = x

Time = 1 year

Rate of interest = 5%

Case 2:

Principal = x+800

Time = 1 year

Rate of interest = 10%

Interest = Amount - principal = 880+1.1x-x=880+0.1x

Her total interest for a year is $250

So,

So the amount she invested at 5% annual interest is $1133.33

She invested at 10% annual interest=x+800=1133.33+800=1933.33

Hence she have $1133.33 in account which pays  5% annual interest and he have $1933.33 in account which pays 10% annual interest

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

hi how are you doing today? if you ever need just tell me

step-by-step explanation: