Given the function f(x) = 4(2)x, section a is from x = 1 to x = 2 and section b is from x = 3 to x = 4.

part a: find the average rate of change of each section. (4 points)

part b: how many times greater is the average rate of change of section b than section a? explain why one rate of change is greater than the other. (6 points)

(10 points)

Part A: Section A- 8, Section B- 32.

Part B: 4 times.

Step-by-step explanation:

The function is given by .

Section A is from x = 1 to x = 2.

Now, f(1) = 4 × 2 = 8 and f(2) = 4 × 2 × 2 = 16

Again, section B is from x = 3 to x = 4.

Now, f(3) = 4 × 2 × 2 × 2 = 32 and f(4) = 4 × 2 × 2 × 2 × 2 = 64

Part A:

In section A, the average rate of change is = (Answer)

And in section B, the average rate of change is  = (Answer)

Part B:

Therefore, the number of times the average rate of change of section B is greater than section A is (Answer)

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3