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find the number of real number solutions for the equation. x2 + 5x + 7 = 0
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Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

The number of real solutions for the equation is zero

Solution:

For a Quadratic Equation of form :  ---- eqn 1

The solution is  

Now , the given Quadratic Equation is  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In , is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x