Select is a function or is not a function to correctly classify each relation. title is a function is not a function {(28)} {(04)} {(13)} {(33)}

The answer is:

{(2,2),(4,4),(6,6),(8,8)} is a function

{(0,3),(3,5),(5,6),(8,4)} is a function

{(1,2),(3,3),(4,8),(6,3)} is a function

{(3,4),(5,2),(5,6),(7,3)} is not a function

Step-by-step explanation:

Sorry I don't have an explanation, but I know these are correct because I took the test and got this correct. ;)

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: