Acompany deposits $25,000 in a bank account that earns interest. the value of the account can be represented as 25,000e^0.0198t, where t represents time, in years.

the time, t, in years that it will take for the account to have a value of $30,000 can be modeled as t=ln(k)/0.0198. what is the value of k?

  k = 1.2

Step-by-step explanation:

Solving for t when the account value is 30,000, we have ...

  30,000 = 25,000e^(0.0198t)

  30,000/25,000 = 1.2 = e^(0.0198t)

  ln(1.2) = 0.0198t

  t = ln(1.2)/0.0198

Matching this with the form ...

  t = ln(k)/0.0198

we see that k = 1.2.

k is the multiplier of account value in time period t.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.