Alocal hamburger shop sold a combined total of 500 hamburgers and cheeseburgers on tuesday. there were 50 fewer cheeseburgers sold than hamburgers.
how many hamburgers were sold on tuesday?

275

Step-by-step explanation:

Let the total number of hamburger be x and the total number of cheeseburgers be y. That is

x + y = 500 equation 1

Since there were 50 fewer cheeseburgers sold than hamburgers, this means that the number of hamburgers sold is more than cheeseburgers by 50 , that is

x - y = 50 equation 2

solving the resulting linear equation by substitution method;

From equation 2 , make x the subject of the formula , that is

x = 50 + y equation 3

substitute equation 3 into equation 1 , we have

50 + y + y = 500

50 + 2y = 500

2y = 500 - 50

2y = 450

y = 450/2

y = 225

substitute y = 225 into equation 3 to find the value of x. we have

x = 50 + y

x = 50 + 225

x = 275

Therefore 275 hamburgers were sold

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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